Comments on: TypeScript Classes & Object-Oriented Programming https://codebelt.github.io/blog/typescript/typescript-classes-object-oriented-programming/ Manage Your Code Snippets with codeBelt | Code Examples / Tutorials / Articles Wed, 14 Feb 2018 05:52:52 +0000 hourly 1 https://wordpress.org/?v=4.9.10 By: robert https://codebelt.github.io/blog/typescript/typescript-classes-object-oriented-programming/#comment-59003 Sun, 06 Dec 2015 20:29:08 +0000 https://codebelt.github.io/blog/?p=1561#comment-59003 The example below doesn’t retrun anything. Notice that there is no ‘return’ keyword at the bottom of the method.

public work():void {
// This method doesn't return anything.
}

Notice that there is a ‘return’ keyword at the bottom of the method. That is how you tell the method to return something.

public work():string {
var str = 'This is the string you are returning';
return str;
}

super() is only need in the constructor when you extend another class. Cat extends Animal Basically this is calling the constructor of the Animal class so that your Cat class inherits all the functionality from the Animal class.

]]> By: gabriel https://codebelt.github.io/blog/typescript/typescript-classes-object-oriented-programming/#comment-58972 Thu, 03 Dec 2015 19:25:12 +0000 https://codebelt.github.io/blog/?p=1561#comment-58972 As a guy that has worked with javascript but is now required to work in an object oriented way (which i’ve never done), this couldn’t be more helpful, thanks. Only doubts that remained are:

If public work():void {(something)} means that the function is expected to return nothing, then if I expect it to return a string for instance, would I write public work():string {(something)}

And, what’s the meaning of the ‘super()’ keyword you used in the constructor of the cat class?

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